2013CAP Prize Exam加拿大高中物理大奖赛真题答案下载

历年CAP High School Prize Exam加拿大高中物理大奖赛

真题与答案下载

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2013 CAP Prize Exam完整版真题免费下载

共计3小时考试时间

此套试卷由25道选择题以及3道大题组成

每道大题含有不同数量的小题

2013CAP Prize Exam加拿大物理奥林匹克完整版答案免费下载

部分真题答案预览：

Part A选择题部分：

1. A
2. C
3. A
4. A
5. A

Part B简答题部分

Solution to Problem 1：

The internal resistance of the capacitor is small compared with the dynamic resistance of the diode at the operating current, so it can be ignored.

Q(t)/C+ R(t)I + VLED =0

I = I0 is to be kept constant at 800 mA, so

Q(t)= Q0 − I0 t

... where Q0 is the initial charge.

Q0 = V0 C (Q0 − I0 t)/C− R(t)I0 − VLED =0 V0 − I0 t/C − R(t)I0 − VLED =0 V0 /I0 − t/C − R(t)− VLED/I0 =0 R(t)= −t/C − VLED/I0 + V0 /I0

Therefore R0 has to be R0 =(V0 − VLED)/I0 =(5− 2.7)/0.5=2.9Ω

R(t)= −t/C + R0 = R0 − t/C

R(t)cannot be negative, so tmax = R0 C =3000× 2.9 =8600 s,thatis2.4hours.

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