2015CAP Prize Exam加拿大高中物理大奖赛真题答案下载

历年CAP High School Prize Exam加拿大高中物理大奖赛

真题与答案下载

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2015 CAP Prize Exam完整版真题免费下载

共计3小时考试时间

此套试卷由25道选择题以及3道大题组成

每道大题含有不同数量的小题

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2015 CAP Prize Exam完整版真题

2015CAP Prize Exam加拿大物理奥林匹克完整版答案免费下载

部分真题答案预览：

Part A选择题部分：

1. D
2. D
3. C
4. B
5. A

Part B简答题部分

Solution to Problem 1：

1. From the red dashed red triangle on the picture one can measure the shooting angle to be θ = (22 ± 3⁰). Using the scale of the graph and attached to the exam “ruler” one can measure the maximum height above the end of the shooter h =( 9 ± 2) m and the horizontal distance from the end of the shooter to the place of maximum height L = (33 ± 2) m as well as the height H = 35m from the maximum to the drop point and total range  L’ = (83 ± 2) m

 

From the conservation of energy we have:

mgh + m(vcosθ)2/2 =  mv2/2

v = √2gh/(1-cosθ)2 =  √2gh/sinθ2 = 35 ± 8 m/s

2. Horizontal speed is vh= v cosθ = 32 m/s and it should be constant without air resistance. Due to acceleration g it should take t1 =√2h/g = 1.3    to reach height h and  t2 = √2H/g    = 2.7 s to drop to the bottom.  During this time gravel should cover a distance of about 140 m. The observed range is much smaller (83 m) due to the air resistance.
3. The average horizontal speed is about

 

va = 83/4 = 21 m/s.

The final speed is:

va = (vh+vf)/2  vf = 2va  - vh  = 7 m/s

so the negative acceleration due to air resistance is

vf = vh – at    a = (vh – vf)/t = 6m/s2

So the force acting on (for example) 1 kg of gravel was about 10 N. It is clear from the photograph that it strongly depend on the size of stones.

There were many ways to solve this problem and all the fully correct ones were awarded full marks and partly correct ones part marks.   

 

 

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