The probability, per second, that a given nucleus will decay
Americium-241 is an artificially produced radioactive element that emits α-particles. A sample of americium-241 of mass 5.1 μg is found to have an activity of 5.9 × 105 Bq.
Part (a)
Step 1: Write down the known quantities
Step 2: Write down the equation relating number of nuclei, mass and molecular mass
Step 3: Calculate the number of nuclei
Part (b)
Step 1: Write the equation for activity
Activity, A = λN
Step 2: Rearrange for decay constant λ and calculate the answer
Radioactive decay follows an exponential pattern. The graph shows three different isotopes each with a different rate of decay
Radioactive Decay Equation
N = N0e–λt
The exponential function e
Strontium-90 decays with the emission of a β-particle to form Yttrium-90. The decay constant of Strontium-90 is 0.025 year-1.
Determine the activity A of the sample after 5.0 years, expressing the answer as a fraction of the initial activity A0
Step 1: Write out the known quantities
Decay constant, λ = 0.025 year-1
Time interval, t = 5.0 years
Both quantities have the same unit, so there is no need for conversion
Step 2: Write the equation for activity in exponential form
A = A0e–λt
Step 3: Rearrange the equation for the ratio between A and A0
Step 4: Calculate the ratio A/A0
Therefore, the activity of Strontium-90 decreases by a factor of 0.88, or 12%, after 5 years
The time taken for half the number of nuclei in a sample to decay
When a time equal to the half-life passes, the activity falls by half, when two half-lives pass, the activity falls by another half (which is a quarter of the initial value)
N = N0 e–λt
Strontium-90 is a radioactive isotope with a half-life of 28.0 years.A sample of Strontium-90 has an activity of 6.4 × 109 Bq. Calculate the decay constant λ, in s–1, of Strontium-90.
Step 1: Convert the half-life into seconds
Step 2: Write the equation for half-life
Step 3: Rearrange for λ and calculate
Although you may not be expected to derive the half-life equation, make sure you're comfortable with how to use it in calculations such as that in the worked example.
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