the energy required to raise the temperature of one kilogram of a substance by one kelvin
Explanation of Heat Energy
ΔE = mcΔθ
Examples of heat energy
An absolute temperature scale where each degree is the same size as those on the Celsius scale
Low v high specific heat capacity
Table of values of specific heat capacity for various substances
Water of mass 0.48 kg is increased in temperature by 0.7 K. The specific heat capacity of water is 4200 J kg-1 K-1. Calculate the amount of energy transferred to the water.
Step 1: Write down the known quantities
Step 2: Write down the relevant equation
ΔE = mcΔθ
Step 3: Calculate the energy transferred by substituting in the values
ΔE = (0.48) × (4200) × (0.7) = 1411.2
Step 4: Round the answer to 2 significant figures
ΔE = 1400 J
You will always be given the specific heat capacity of a substance, so you do not need to memorise any values. Make sure that Δθ is the change in temperature, therefore, it can be in K or °C.
The example of changes of state between solids, liquids and gases
The thermal energy required to change the state of one kilogram of a substance without any change of temperature
The changes of state with heat supplied against temperature. There is no change in temperature during changes of state
The thermal energy required to convert one kilogram of solid to liquid with no change in temperature
The thermal energy required to convert one kilogram of liquid to gas with no change in temperature
ΔE = LΔm
The energy needed to boil a mass of 530 g of a liquid is 0.6 MJ. Calculate the specific latent heat of the liquid and state whether it is the latent heat of vaporisation or fusion.
Step 1: Substitute in the values
L is the latent heat of vaporisation because the change in state is from liquid to gas (boiling)
Use these reminders to help you remember which type of latent heat is being referred to:
转载自savemyexams
© 2024. All Rights Reserved. 沪ICP备2023009024号-1