Electrons are emitted from the (negative) cathode and accelerated to the (positive) anode
Electron guns use electric fields to accelerate electrons to very high speeds.
Show that an electron accelerated from rest across a potential difference of 5.0 kV attains a speed of 4.2 × 107 m s–1.
Use the following data:
Step 1: List the known quantities
Step 2: Equate the kinetic energy gained by the electron to the energy transferred across the potential difference
Step 3: Make speed v the subject of the equation
Step 4: Substitute quantities and calculate the speed v
= 41 908 313... = 4.2 × 107 m s–1
Examiners commonly test if candidates can equate the energy gained across a potential difference with the kinetic energy of a particle, as we did here. Make sure you can combine the equations for kinetic energy and potential energy in order to calculate speed like we did here!
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