The product of the magnetic flux density and the cross-sectional area perpendicular to the direction of the magnetic flux density
Φ = BA
The magnetic flux is maximised when the magnetic field lines and the area through which they are passing through are perpendicular
Φ = BA cos(θ)
The magnetic flux decreases as the angle between the field lines and plane decrease
The product of the magnetic flux and the number of turns of the coil
Flux linkage = ΦN = BAN
An aluminium window frame has a width of 40 cm and length of 73 cm as shown in the figure belowThe frame is hinged along the vertical edge AC. When the window is closed, the frame is normal to the Earth’s magnetic field with magnetic flux density 1.8 × 10-5 T
a) Calculate the magnetic flux through the window when it is closed
b) Sketch the graph of the magnetic flux against angle between the field lines and the normal when the window is opened and rotated by 180°
Part (a)
Step 1: Write out the known quantities
Cross-sectional area, A = 40 cm × 73 cm = (40 × 10-2) × (73 × 10-2) = 0.292 m2
Magnetic flux density, B = 1.8 × 10-5 T
Step 2: Write down the equation for magnetic flux
Φ = BA
Step 3: Substitute in values
Φ = (1.8 × 10-5) × 0.292 = 5.256 × 10-6 = 5.3 × 10-6 Wb
Part (b)
The magnetic flux will be at a minimum when the window is opened by 90o and a maximum when fully closed or opened to 180o
A solenoid of circular cross-sectional radius 0.40 m and 300 turns is placed perpendicular to a magnetic field with a magnetic flux density of 5.1 mT.
Determine the magnetic flux linkage for this solenoid.
Step 1: Write out the known quantities
Step 2: Write down the equation for the magnetic flux linkage
ΦN = BAN
Step 3: Substitute in values and calculate
ΦN = (5.1 × 10-3) × 0.503 × 300 = 0.7691 = 0.8 Wb turns (2 s.f)
Consider carefully the value of θ, it is the angle between the field lines and the line normal (perpendicular) to the plane of the area the field lines are passing through. If it helps, drawing the normal on the area provided will help visualise the correct angle.
Just like for magnetic flux, the flux linkage through a coil may not be entirely perpendicular.
The magnetic flux linkage through a rectangular coil decreases as the angle between the field lines and a normal line to the coil plane decreases
In this case, you can just substitute the equation for B into the equation for φN, such that the flux linkage is calculated by:
As before, you should remember that since cos (0°) = 1, the flux linkage is a maximum when the angle θ is zero. This means the flux and coil face are perpendicular (i.e. the normal line to the coil face and the flux lines are parallel).
转载自savemyexams
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