The ratio of the useful power or energy transfer output from a system to its total power or energy transfer input



An electric motor has an efficiency of 35 %. It lifts a 7.2 kg load through a height of 5 m in 3 s.
Calculate the power of the motor.
Step 1: Write down the efficiency equation

Step 2: Rearrange for the power input 
Step 3: Calculate the power output
Gravitational potential energy = mgh = 7.2 × 9.81 × 5 = 353.16 J
Power = 353.16 ÷ 3 = 117.72 W
Step 4: Substitute values into power input equation 
The diagram shows a pump called a hydraulic ram.
In one such pump, the long approach pipe holds 700 kg of water. A valve shuts when the speed of this water reaches 3.5 m s-1 and the kinetic energy of this water is used to lift a small quantity of water by height of 12m.
The efficiency of the pump is 20%.
Determine the mass of water which could be lifted 12 m
Step 1: Identify the energy conversions and write them in an equation

Step 2: Include the efficiency in the equation

Step 3: Substitute in the values and calculate

Step 4: Write the answer with the correct significant figures and units
In efficiency calculations decide before starting where the energy is lost from the system.
In the example above, the pump is what converts the water’s kinetic energy into gravitational potential energy, and it is the pump whose efficiency we are given. That means the losses are from the kinetic energy.
Don't just calculate then deduct the efficiency at the end - this can lead to lots of work for no marks. Which isn't very efficient!
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