A + B → C + D
Elementary step 1: A → R + D
Elementary step 2: R + B → C
A + R + B → R + C + D
A + B → C + D
Sulfur dioxide reacts with oxygen to form sulfur trioxide
Answers
Answer 1:
Answer 2:
Elementary step 1: 2NO + O2 → 2NO2
Elementary step 2: NO2 + SO2 → NO + SO3 (or 2NO2 + 2SO2 → 2NO + 2SO3)
It is important that you check that the equations you are proposing for a reaction mechanism.They must add up to the overall stoichiometric equation, otherwise the proposed mechanism is wrong.
NO2 (g) + CO (g) → NO (g) + CO2 (g)
Rate = k [NO2]2
Step 1:
2NO2 (g) → NO (g) + NO3 (g) slow (rate-determining step)
Step 2:
NO3 (g) + CO (g) → NO2 (g) + CO2 (g) fast
Overall:
2NO2 (g) + NO3 (g) + CO (g) → NO (g) + NO3 (g) + NO2 (g) + CO2 (g)
= NO2 (g) + CO (g) → NO (g) + CO2 (g)
It is important that the elementary steps for a proposed mechanism also agree with the experimentally determined rate equationThe rate equation and the overall reaction must be related, i.e. the correct chemical species involvedRemember: There is no direct link between the orders in the rate equation and the stoichiometry of the overall equationHowever, the rate equation can be derived directly from the rate determining step and its stoichiometry
2NO (g) + 2H2 (g) → N2 (g) + 2H2O (l)
Step 1:
NO (g) + NO (g) → N2O2 (g) fast
Step 2:
N2O2 (g) + H2 (g) → H2O (l) + N2O (g) slow (rate-determining step)
Step 3:
N2O (g) + H2 (g) → N2 (g) + H2O (l) fast
Rate = k [NO]2 [H2]
Intermediates in the mechanism cannot appear as substances in the rate equationThis is why you substitute the N2O2 in the above example. Step 1 shows that 2NO molecules are required to form the necessary N2O2
The mechanism of nucleophilic substitution in 2-bromo-2-methylpropane which is a tertiary halogenoalkane
The SN2 mechanism of bromoethane with hydroxide causing an inversion of configuration
Primary halogenoalkanes only react via with SN2 mechanism
Secondary halogenoalkanes react via both the SN1 and SN2 mechanisms
Tertiary halogenoalkanes only react via with SN1 mechanism
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