Edexcel A Level Chemistry:复习笔记5.1.1 Deducing Kp Expressions
Kp Expressions
- We have seen previously that equilibrium reactions can be quantified by reference to an equilibrium expression and equilibrium constant
- The equilibrium expression links the equilibrium constant, Kc, to the concentrations of reactants and products at equilibrium taking the stoichiometry of the equation into account
- So, for a given reaction:
aA + bB ⇌ cC + dD
Kc is defined as follows:
Equilibrium expression linking the equilibrium concentration of reactants and products at equilibrium
- Solids are ignored in equilibrium expressions
- The Kc of a reaction is constant and only changes if the temperature of the reaction changes
Homogeneous reactions
- In the generic example above, if all the substances are gases, we can show the equation with that state symbol
aA (g) + bB (g) ⇌ cC (g) + dD (g)
- We can write a different equilibrium expression in terms of the partial pressure of the gases
- This equilibrium constant is called Kp and is defined as follows
Equilibrium expression linking the partial pressures of reactants and products at equilibrium
Heterogeneous reactions
- For heterogenous reactions, solids and liquids are ignored in Kp equilibrium expressions
- The Kp of a reaction is constant and only changes if the temperature of the reaction changes
Worked Example
Write a Kp expression for the following equilibria and deduce the units of Kp :
- N2 (g) + 3H2 (g) ⇌ 2NH3 (g)
- CaCO3 (s) ⇌ CaO (s) + CO2 (g)
Answer 1
Answer 2
Kp = pCO2(g) = kPa
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