To break bonds energy is required from the surroundings and to make new bonds energy is released from the reaction to the surroundings
Overall enthalpy changes
Bond enthalpy profiles
'The energy needed to break one mole of bonds in a gaseous molecule averaged over similar compounds'
Average bond enthalpy of C-H in methane
A lot of students mix up endothermic / exothermic and bond breaking / bond making.
An easy way to remember is that ENDOTHERMIC leads to the poetic phrase the 'end o' the bond'
ΔrHθ = enthalpy change for bonds broken + enthalpy change for bonds formed
Calculate the enthalpy of reaction for the Haber process reaction. The relevant bond energies are given in the table below:
Answer:
Step 1: The chemical equation for the Haber process is:
N2 (g) + 3H2 (g) ⇌ 2NH3 (g)
N≡N 3 H-H 6 N-H
Step 2: Set out the calculation as a balance sheet as shown below:
Note! Values for bonds broken are positive (endothermic) and values for bonds formed are negative (exothermic)
Step 3: Calculate the standard enthalpy of reaction
The complete combustion of ethyne, C2H2 , is shown in the equation below:
2C2H2 (g) + 5 O2 (g) → 2H2O (g) + 4CO2 (g)
Using the average bond enthalpies given in the table, what is the enthalpy of combustion of ethyne?
Answer:
Step 1: The enthalpy of combustion is the enthalpy change when one mole of a substance reacts in excess oxygen to produce water and carbon dioxide
The chemical reaction should therefore be simplified such that only one mole of ethyne reacts in excess oxygen:
H-C≡C-H + 2 ½ O=O → H-O-H + 2O=C=O
Step 2: Set out the calculation as a balance sheet as shown below:
The key to success in bond enthalpy calculations is to be very careful when accounting for every bond present. Always draw out the full displayed structures of the molecules so you don't miss any of the bonds.
Watch out for coefficients in the balanced equations as students often miss those, forget to multiply them by the bond enthalpies and get the answer wrong!
It is super important to show your steps because bond enthalpy calculations often carry 3 marks, 2 of which could be for workings if you get the final answer wrong
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