The force acting per unit current per unit length on a current-carrying conductor placed perpendicular to the magnetic field
A straight conductor carrying a current of 1A normal to a magnetic field of flux density of 1 T with force per unit length of the conductor of 1 N m-1
A 15 cm length of wire is placed vertically and at right angels to a magnetic field.When a current of 3.0 A flows in the wire vertically upwards, a force of 0.04 N acts on it to the left.Determine the flux density of the field and its direction.
Step 1: Write out the known quantities
Force on wire, F = 0.04 N
Current, I = 3.0 A
Length of wire = 15 cm = 15 × 10-2 m
Step 2: Magnetic flux density B equation
Step 3: Substitute in values
Step 4: Determine the direction of the B field
Using Fleming’s left-hand rule :
F = to the left
I = vertically upwards
therefore, B = into the page
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