a = −⍵2x
The acceleration of an object in SHM is directly proportional to the negative displacement
x = x0sin(⍵t)
x = x0cos(⍵t)
These two graphs represent the same SHM. The difference is the starting position
A mass of 55 g is suspended from a fixed point by means of a spring. The stationary mass is pulled vertically downwards through a distance of 4.3 cm and then released at t = 0.
The mass is observed to perform simple harmonic motion with a period of 0.8 s.
Calculate the displacement x in cm of the mass at time t = 0.3 s.
Step 1: Write down the SHM displacement equation
x = x0 cos(⍵t)
Step 2: Calculate angular frequency
Step 3: Substitute values into the displacement equation
x = 4.3 cos (7.85 × 0.3) = –3.0369… = –3.0 cm (2 s.f)
Since displacement is a vector quantity, remember to keep the minus sign in your solutions if they are negative, you could lose a mark if not!
Also, remember that your calculator must be in radians mode when using the cosine and sine functions. This is because the angular frequency ⍵ is calculated in rad s-1, not degrees.
You often have to convert between time period T, frequency f and angular frequency ⍵ for many exam questions – so make sure you revise the equations relating to these.
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