The work done in bringing a mass from infinity to that point
ΔG.P.E = mgΔh
Change in gravitational potential energy between two points
Change in gravitational potential between two points
Gravitational potential energy increases as a satellite leaves the surface of the Moon
A spacecraft of mass 300 kg leaves the surface of Mars to an altitude of 700 km.Calculate the change in gravitational potential energy of the spacecraft.Radius of Mars = 3400 km
Mass of Mars = 6.40 x 1023 kg
Step 1: Difference in gravitational potential energy equation
Step 2: Determine values for r1 and r2
r1 is the radius of Mars = 3400 km = 3400 × 103 m
r2 is the radius + altitude = 3400 + 700 = 4100 km = 4100 × 103 m
Step 3: Substitute in values
ΔG.P.E = 643.076 × 106 = 640 MJ (2 s.f.)
Make sure to not confuse the ΔG.P.E equation with
ΔG.P.E = mgΔh
The above equation is only relevant for an object lifted in a uniform gravitational field (close to the Earth’s surface). The new equation for G.P.E will not include g, because this varies for different planets and is no longer a constant (decreases by 1/r2) outside the surface of a planet.
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