The gravitational field strength at a point describes how strong or weak a gravitational field is at that point
The gravitational field strength due to a point mass can be derived from combining the equations for Newton’s law of gravitation and gravitational field strength
For calculations involving gravitational forces, a spherical mass can be treated as a point mass at the centre of the sphere
Newton’s law of gravitation states that the attractive force F between two masses M and m with separation r is equal to:
The gravitational field strength at a point is defined as the force F per unit mass m
Substituting the force F with the gravitational force FG leads to:
Cancelling mass m, the equation becomes:
Where:
g = gravitational field strength (N kg-1)
G = Newton’s Gravitational Constant
M = mass of the body producing the gravitational field (kg)
r = distance from the mass where you are calculating the field strength (m)
Calculating g
Gravitational field strength, g, is a vector quantity
The direction of g is always towards the centre of the body creating the gravitational field
This is the same direction as the gravitational field lines
On the Earth’s surface, g has a constant value of 9.81 N kg-1
However outside the Earth’s surface, g is not constant
g decreases as r increases by a factor of 1/r2
This is an inverse square law relationship with distance
When g is plotted against the distance from the centre of a planet, r has two parts:
When r < R, the radius of the planet, g is directly proportional to r
When r > R, g is inversely proportional to r2(this is an ‘L’ shaped curve and shows that g decreases rapidly with increasing distance r)
Graph showing how gravitational field strength varies at greater distance from the Earth’s surface
Sometimes, g is referred to as the ‘acceleration due to gravity’ with units of m s-2
Any object that falls freely in a uniform gravitational field on Earth has an acceleration of 9.81 m s-2
Worked Example
The mean density of the moon is ⅗ times the mean density of the Earth. The gravitational field strength is ⅙ on the Moon than that on Earth.Determine the ratio of the Moon’s radius rM and the Earth’s radius rE.
Step 1: Write down the known quantities gM = gravitational field strength on the Moon, ρM = mean density of the Moon
gE = gravitational field strength on the Earth, ρE = mean density of the Earth Step 2: The volumes of the Earth and Moon are equal to the volume of a sphere Step 3: Write the density equation and rearrange for mass M M = ρV
Step 4: Write the gravitational field strength equation Step 5: Substitute M in terms of ρ and V Step 6: Substitute the volume of a sphere equation for V, and simplify
Step 7: Find the ratio of the gravitational field strengths Step 8: Rearrange and calculate the ratio of the Moon’s radius rM and the Earth’s radius rE