ΔGꝋ = - n x Ecellꝋ x F
ΔGꝋ = standard Gibbs free energy
n = number of electrons transferred in the reaction
Ecellꝋ = standard cell potential (V)
F = Faraday constant (96 500 C mol-1)
Answer
Fe3+ (aq) + e- ⇌ Fe2+ (aq) Eꝋ = +0.77 V
Cu2+ (aq) + 2e- ⇌ Cu (s) Eꝋ = +0.34 V
Ecellꝋ = Eredꝋ - Eoxꝋ
= (+0.77) - (+0.34)
= +0.43 V
The Cu2+/Cu has a smaller Eꝋ value which means that it gets oxidised
It transfers two electrons to two Fe3+ ions
Each Fe3+ ion accepts one electron so the total number of electrons transferred is two
ΔGꝋ = - n x Ecellꝋ x F
= -2 x (+0.43) x 96 500
= -82 990 J mol-1
= -83 kJ mol-1
转载自savemyexams
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