The graph shows that both the first and second ionization energies decrease going down the table
The atomic radius of the Group 2 elements increases going down the group due to the addition of an extra principal quantum shell
The graph shows a increase in atomic radius going down the group
The graph shows a decrease in melting point going down the group
The graph shows an increase in density going down the group
Answer
Property 1:
Since, Ra is in Group 2, it will form an ion with +2 charge to give Ra2+Property 2:
The Group 2 oxides and hydroxides have general formula XO and X(OH)2 respectively where X is the Group 2 element.Therefore, radium oxide is RaO and radium hydroxide is Ra(OH)2
Property 3:
Radium is below barium so its atomic radius is larger than the atomic radius of barium.
This means that radium’s outermost electrons are even further away and are therefore even more easily removed than barium’s outermost electron pair.The first ionization energy is between 450-480 kJ mol-1
Property 4:
Radium’s outermost electrons are even further away than in barium and are therefore more easily removed making radium more reactive than barium.
Property 5:
The Group 2 hydroxides become more soluble going down the group.
Radium hydroxide will therefore be more soluble than calcium hydroxide.Property 6:
The Group 2 sulfates become less soluble going down the group.Radium sulfate will therefore be less soluble than strontium sulfate.
Property 7:
The general equation for the reaction of Group 2 oxides with dilute hydrochloric acid is:
XO(s) + 2HCl(aq) → XCl2(aq) + H2O(l)
where X is the Group 2 element
The reaction of radium oxide with dilute hydrochloric acid is therefore:
RaO(s) + 2HCl(aq) → RaCl2(aq) + H2O(l)
Property 8:
Radium sulfate will be formed in this reaction, however the solubility of Group 2 sulfates decreases going down the group, therefore a white precipitate of radium sulfate will be formed in this reaction
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