The diagram above illustrates Hess’ Law: the enthalpy change of the direct route, going from reactants (A+B) to product (C) is equal to the enthalpy change of the indirect routes
3C (s) + 4H2 (g) → C3H8(g)
OR
The enthalpy change from elements to products (direct route) is equal to the enthalpy change of elements forming reactants and then products (indirect route)
ΔH2 = ΔH1 + ΔHr
Therefore,
ΔHr = ΔH2 – ΔH1
Step 4: Apply Hess’s Law
OR
The enthalpy change going from elements to products (direct route) is equal to the enthalpy change of elements forming reactants and then products (indirect route)
ΔH1 = ΔHf + ΔH2
Therefore,
ΔHf = ΔH1 – ΔH2
½ H2(g) → H(g)
Remember to take into account the number of moles of each reactant and product.For example, there are two moles of NaHCO3(s) so the ΔHf value is multiplied by 2.
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