To break bonds energy is required from the surroundings and to make new bonds energy is released from the reaction to the surroundings
Bond energies are affected by other atoms in the molecule
Formula of calculating the standard enthalpy change of reaction using bond energies
Answer
N2 (g) + 3H2 (g) ⇌ 2NH3 (g)
Note! Values for bonds broken are positive (endothermic) and values for bonds formed are negative (exothermic)
ΔHrꝋ = enthalpy change for bonds broken + enthalpy change for bonds formed= (+2253 kJ mol-1) + (-2346 kJ mol-1)= -93 kJ mol-1
Answer
The chemical reaction should be therefore simplified such that only one mole of ethyne reacts in excess oxygen:
H-C=C-H + 2 ½ O=O → H-O-H + 2O=C=O
ΔHrꝋ = enthalpy change for bonds broken + enthalpy change for bonds formed= (+2912 kJ mol-1) + (- 4142 kJ mol-1)= -1230 kJ mol-1
A polystyrene cup can act as a calorimeter to find enthalpy changes in a chemical reaction
Equation for calculating energy transferred in a calorimeter
m (of water) = 500 g
c (of water) = 4.18 J g-1 K-1
ΔT (of water) = 68 oC - 25 oC
= 43 oC
= 43 K
The change in temperature in oC is equal to the change in temperature in K
= 89 870 J
Total energy x 0.3 = 89 870 J
Total energy = 299 567 J
= 119 827 J
= 120 kJ
When new bonds are formed the amount of energy released is equal to the amount of energy absorbed when the same bonds are broken.For example:O2 (g) → 2O (g) E (O=O) = +498 kJ mol-12O (g) → O2 (g) E (O=O) + -498 kJ mol-1 Aqueous solutions of acid, alkalis and salts are assumed to be largely water so you can just use the m and c values of water when calculating the energy transferred. To then calculate any changes in enthalpy per mole of a reactant or product the following relationship can be used:
When there is a rise in temperature, the value for ΔH becomes negative suggesting that the reaction is exothermic and when the temperature falls, the value for ΔH becomes positive suggesting that the reaction is endothermic.Also, remember that the ΔT is the same in oC and K!
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