A copper rod moves within a magnetic field when current is passed through it
F = BIL sinθ
Magnitude of the force on a current carrying conductor depends on the angle of the conductor to the external B field
F = BIL
A current of 0.87 A flows in a wire of length 1.4 m placed at 30o to a magnetic field of flux density 80 mT.Calculate the force on the wire.
Step 1: Write down the known quantities
Magnetic flux density, B = 80 mT = 80 × 10-3 T
Current, I = 0.87 A
Length of wire, L = 1.4 m
Angle between the wire and the magnetic field, θ = 30o
Step 2: Write down the equation for force on a current-carrying conductor
F = BIL sinθ
Step 3: Substitute in values and calculate
F = (80 × 10-3) × (0.87) × (1.4) × sin(30) = 0.04872 = 0.049 N (2 s.f)
Both wires will attract if their currents are in the same direction and repel if in opposite directions
Two long, straight, current-carrying conductors, WX and YZ, are held at a close distance, as shown in diagram 1.
The conductors each carry the same magnitude current in the same direction. A plan view from above the conductors is shown in diagram 2.On diagram 2, draw arrows, one in each case, to show the direction of:
Remember that the direction of current flow is the flow of positive charge (positive to negative), and this is in the opposite direction to the flow of electrons
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