Δp = final momentum – initial momentum
Δp = –mv – mv = –2mv
A particle hitting a wall of the container in which the gas is held experiences a force from the wall and a change in momentum. The particle exerts an equal and opposite force on the wall
2 mol of gas is sealed in a container, at a temperature of 47°C.
Determine:
Part (a)
Step 1: Write down the temperature T of the gas in kelvin (K)
T = 47°C = 320 K
Step 2: Write down the equation linking the absolute temperature T of the gas to the average random kinetic energy EK of the gas particles
Step 3: Substitute numbers into the equation
EK = 6.6 × 10–21 J
Part (b)
Step 1: Write down the equation linking the internal energy U of the gas to the number of moles n and the absolute temperature T
Step 2: Substitute numbers into the equation
U = 8000 J = 8kJ
U = NEK = 8000 J = 8kJ
N = nNA = 2 mol × (6.02 × 1023) mol–1 = 1.2 × 1024
EK = 6.6 × 10–21 J (calculated in Step 3)
Momentum is a Mechanics topic that should have been covered in a previous unit. The above derivation of change in momentum and resultant force should have already been studied - if you're not comfortable with it then make sure you go back to revise this!
转载自savemyexams
© 2024. All Rights Reserved. 沪ICP备2023009024号-1