The energy stored within a material (e.g. in a spring) when it is stretched or compressed
EPE = KE
½ kx2 = ½ mv2
v ∝ x
A car’s shock absorbers make a ride more comfortable by using a spring that absorbs energy when the car goes over a bump. One of these springs, with a force constant of 50 kN m–1 is fixed next to a wheel and compressed a distance of 10 cm.Calculate the energy stored by the compressed spring.
Step 1: List the known values
Step 2: Write the relevant equation
EPE = ½ kx2
Step 3: Substitute in the values
EPE = ½ × (50 × 103) × (10 × 10–2)2 = 250 J
Work done is the area under the force-extension graph
The ultimate breaking stress is the point on the stress-strain graph of maximum stress. The breaking point is where the material fractures
The graph shows the behaviour of a sample of a metal when it is stretched until it starts to undergo plastic deformation.Calculate the total work done in stretching the sample from zero to an extension of 13.5 mm.Simplify the calculation by treating the curve XY as a straight line.
A spring is extended with varying forces; the graph below shows the results.Calculate the energy stored in the spring when the extension is 40 mm.
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