“The enthalpy change when one mole of a compound is formed from its elements under standard conditions”
Enthalpy changes using enthalpy of formation
Given the data:Calculate the enthalpy of combustion of gaseous diborane given that it burns according to the following equation:
B2H6(g) + 3O2(g) → B2O3(s) + 3H2O(g)
Answer
Step 1: Find the sum of the enthalpies of combustion of the products
ΔHf = + ( -1270) + ( - 242 x 3) = - 1996 kJ
Step 2: Find the sum of the enthalpies of combustion of the reactants
ΔHf = + (+31.4) + 0 = + 31.4 kJ
There is no enthalpy of formation for oxygen as ΔHf of elements by definition is zero
Step 3: Calculate the enthalpy change
ΔH = ΔHf products - ΔHf reactants = - 1996 - (+ 31.4) = -2027.4 kJ
In Paper 1, Enthalpy of Formation data will given in the question. For Paper 2, you may need to refer to Section 12 of the Data Booklet where you will find Thermodynamic Data for Selected Compounds
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