Sweet peas grow pods that are either green or yellow. The allele for green, G, is dominant to the allele for yellow, g.Construct a Punnett grid to predict the outcome when crossing green and yellow pure-bred plants to show the F1 generation offspring.Using plants from the F1 generation, construct a second Punnett grid to show the outcomes of the F2 generation.
Step 1: Write down the parental phenotype and genotypes
Green coloured pods Yellow coloured pods
GG gg
Step 2: Write down all the possible gamete genotypes that each parent could produce
Step 3: Place each parental genotype against one axis of a Punnett grid (2 x 2 table)
Step 4: Combine the gametes in each box of the Punnett grid
Genotypes of the F1 cross between homozygous green (GG) and homozygous yellow (gg) pea plants. All offspring (100%) have the genotype Gg and the phenotype is green.
Step 5: Take two heterozygous offspring from the F1 generation and cross them
Step 6: Combine the gametes in each box of the Punnett grid
Punnett grid showing the results of the F2 generation
Phenotype ratio is 3:1 green:yellow, Genotype ratio is 1 GG: 2 Gg: 1 gg
A pure-breeding genetic cross in pea plants. It shows that all offspring will be have the tall phenotype.
A genetic cross diagram (F2 generation). It shows a ratio of 3 tall : 1 short for any offspring.
A cross between a heterozygous plant with a short plant
If you are asked to use your own letters to represent the alleles in a Punnett grid, try to choose a letter that is obviously different as a capital than the lower case so the examiner is not left in any doubt as to which is dominant and which is recessive.
A family pedigree chart
When answering questions about pedigree charts for genetic diseases, it is always useful to remember which phenotype is caused by the recessive allele. You can write these genotypes onto your chart and it will give you a good starting point for working out the possible genotypes of the rest of the individuals in the chart.
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