Phase changes for water
The graph below is the heating curve for a 25 g cube of ice being heated at a constant rate. Calculate:
Step 1: Write down the mass m of ice in kilograms (kg)
m = 25 g = 0.025 kg
Step 2: Read from the graph the amount of energy E1 being supplied to the water in its liquid phase as it warms up
E1 = 20 kJ – 10 kJ = 10 kJ
Step 3: Convert this energy from kilojoules into joules
E1 = 10 kJ = 10000 J
Step 4: Read from the graph the change in temperature ΔT1 of the water as it warms up
ΔT1 = 100°C – 0°C = 100°C
Step 5: Write down the equation linking thermal energy E1 to mass m, specific heat capacity c and change in temperature ΔT1
E1 = mcΔT1
Step 6: Solve for the specific heat capacity c
c = 4000 J kg–1 °C–1
Step 7: Read from the graph the amount of energy E2 being supplied to the water as it changes into a gas at 100°C
E2= 56 kJ = 56000 J
Step 8: Write down the equation linking thermal energy E2 to mass m and specific latent heat of vaporisation Lv
E2 = mLv
Step 9: Solve for the specific latent heat of fusion Lv
Lv = 2.2 × 106 J kg–1
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