The amount of energy required to raise the temperature of 1 kg of the substance by 1 °C
Low vs high specific heat capacity
Change in thermal energy = Mass × Specific heat capacity × Change in temperature
ΔQ = mcΔT
Water of mass 0.48 kg is increased in temperature by 0.7 °C. The specific heat capacity of water is 4200 J / kg °C.Calculate the amount of thermal energy transferred to the water.
Step 1: Write down the known quantities
Step 2: Write down the relevant equation
ΔQ = mcΔT
Step 3: Calculate the thermal energy transferred by substituting in the values
ΔQ = (0.48) × (4200) × (0.7) = 1411.2
Step 4: Round the answer to 2 significant figures
ΔQ = 1400 J
This equation will be given on your equation sheet, so don't worry if you cannot remember it, but it is important that you understand how to use it. You will always be given the specific heat capacity of a substance, so you do not need to memorise any values.
转载自savemyexam
© 2024. All Rights Reserved. 沪ICP备2023009024号-1