The angle of incidence is greater than the critical angle and the incident material is denser than the second material
Critical angle and total internal reflection
Total internal reflection is utilised in:
Optical Fibres
Optical fibres utilise total internal reflection for communications
Endoscopes utilise total internal reflection to see inside a patient's body
Reflection of light through a periscope
Single and double reflection through right-angled prisms
If asked to name the phenomena make sure you give the whole name – total internal reflectionRemember: total internal reflection occurs when going from a denser material to less dense material and ALL of the light is reflectedIf asked to give an example of a use of total internal reflection, first state the name of the object that causes the reflection (e.g. a right-angled prism) and then name the device in which it is used (e.g. a periscope)
As the angle of incidence increases it will eventually surplus the critical angle and lead to total internal reflection of the light
A glass cube is held in contact with a liquid and a light ray is directed at a vertical face of the cube.The angle of incidence at the vertical face is 39° and the angle of refraction is 25° as shown in the diagram.The light ray is totally internally reflected for the first time at X.
Complete the diagram to show the path of the ray beyond X to the air and calculate the critical angle for the glass-liquid boundary.
Step 1: Draw the reflected angle at the glass-liquid boundary
Step 2: Draw the refracted angle at the glass-air boundary
Step 3: Calculate the critical angle
If you are asked to explain what is meant by the critical angle in an exam, you can be sure to gain full marks by drawing and labelling the same diagram above (showing the three semi-circular blocks)
Opals and diamonds are transparent stones used in jewellery. Jewellers shape the stones so that light is reflected inside.Compare the critical angles of opal and diamond and explain which stone would appear to sparkle more.
The refractive index of opal is about 1.5
The refractive index of diamond is about 2.4
Step 1: List the known quantities
Step 2: Write out the equation relating critical angle and refractive index
Step 3: Calculate the critical angle of opal (co)
sin(co) = 1 ÷ 1.5 = 0.6667
co = sin–1 (0.6667) = 41.8 = 42°
Step 4: Calculate the critical angle of diamond (cd)
sin(cd) = 1 ÷ 2.4 = 0.4167
cd = sin–1 (0.4167) = 24.6 = 25°
Step 5: Compare the two values and write a conclusion
When calculating the value of the critical angle using the above equation:
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