a m s-2 is the acceleration of the system
m1 kg and m2 kg are the masses of the two bodies
m1 g N and m2 g N are the weights of the two bodies
T N is the tension in the string
D N is the driving force of the system
F1 N and F2 N are the resistive forces acting on the two bodies
R1 N and R2 N are the normal reaction forces of the two bodies
* You do not necessarily need all diagrams but if in doubt draw all as they may help you to understand the problem more clearly **
Horizontally (→) D - (F1 + F2) = (m1 + m2)a
There is no vertical motion so use “F = 0”
(↑) (R1 + R2) - (m1 + m2)g = 0
(F= ma with a =0 will lead to the same equation)
Particle 1: Horizontally (→) T - F1 = m1a
Vertically(↑) R1 -m1g = 0 (No motion)
Particle 2: Horizontally (→) D - T- F2 = m2a
Vertically(↑) R2 - m2g = 0 (No motion)
(a) Find the engine force from the plane.
(b) Find the tension in the tow rope.
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