The ratio of the permittivity of a material to the permittivity of free space
Calculate the permittivity of a material that has a relative permittivity of 4.5 × 1011.State an appropriate unit for your answer.
Step 1: Write down the relative permittivity equation
Step 2: Rearrange for permittivity of the material ε
ε = εrε0
Step 3: Substitute in the values
ε = (4.5 × 1011) × (8.85 × 10-12) = 3.9825 = 4 F m-1
The electric field of the polar molecules opposes that of the electric field produced by the parallel plates
A parallel plate capacitor consists of conductive plates each with area A, a distance d apart and a dielectric ε between them
A parallel-plate capacitor has square plates of length L separated by distance d and is filled with a dielectric. A second capacitor has square plates of length 3L separated by distance 3d and has air as its dielectric. Both capacitors have the same capacitance.
Determine the relative permittivity of the dielectric in the first capacitor.
Remember that A, the cross-sectional area, is only for one of the parallel plates. Don't multiply this by 2 for both the plates for the capacitance equation!
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