When the force is not constant, the impulse is the area under a force–time graph
Impulse = Force × Change in time
A ball of mass 3.0 kg, initially at rest, is acted on by a force F which varies with t as shown by the graph.Calculate the velocity of the ball after 16 s.
Step 1: List the known quantities
m = 3.0 kg
u = 0 m s-1 (since it is initially at rest)
Step 2: Calculate the impulse
The impulse is the area under the graph. The graph can be split up into two right-angled triangles with a base of 8 s and a height of 4 kN
Area = impulse = 32 × 103 Ns
Step 3: Write the equation for impulse
Impulse, I = Δp = m(v – u)
Step 4: Substitute in the values
I = mv
32 × 103 = 3.0 × v
v = (32 × 103) ÷ 3.0
v = 10666 m s–1 = 11 km s-1
Some maths tips for this section:Rate of Change
Areas
A cricket fielder moves their hands backwards when catching a cricket ball to reduce the force it will exert on their hands
The follow through action of a football kick increases the change in momentum of the ball
A tennis ball hits a racket with a change in momentum of 0.5 kg m s-1.For the different contact times, which tennis racket experiences more force from the tennis ball?
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