Example of a working out what is conserved in Kaon decay. This decay must be through the weak interaction since S is not conserved
The lambda nought particle Λ0 is made up from the quarks uds.Show, in terms of the conservation of charge, strangeness, baryon number and lepton number whether the following interaction is permitted
Step 1: Determine conservation of charge
0 = –1 + 1 + 0
Charge is conserved
Step 2: Determine conservation of strangeness
Λ0 has an s quark, so must have a strangeness of –1
–1 = 0 + 0 + 0
Strangeness is not conserved
Step 3: Determine conservation of baryon number
Λ0 is a baryon since it has 3 quarks, so must have a baryon number of +1
+1 = 0 + 0 + 0
Baryon number is not conserved
Step 4: Determine conservation of lepton number
Λ0 is a baryon, so must have a lepton number of 0
0 = 0 + (–1) + 1
Lepton number is conserved
Step 5: Conclusion
Since the baryon number is not conserved, this interaction is not permitted
The equation for β– decay isUsing the quark model of beta decay, prove that the charge is conserved in this equation.
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