Cl2 (g) + 2e- ⇌ 2Cl- (aq) Eꝋ = +1.36 V
Cu2+ (aq) + 2e- ⇌ Cu (s) Eꝋ = +0.34 V
The electrons flow through the wires from the negative pole to the positive pole
Cl2 (g) + 2e- ⇌ 2Cl- (aq) Eꝋ = +1.36 V
Cu2+ (aq) + 2e- ⇌ Cu (s) Eꝋ = +0.34 V
Cl2 (g) + 2e- → 2Cl- (aq)
Cu (s) → Cu2+ (aq) + 2e-
Cu (s) + Cl2 (g) → 2Cl- (aq) + Cu2+ (aq)
OR
Cu (s) + Cl2 (g) → CuCl2 (s)
A reaction is feasible when the standard cell potential Eꝋ is positive
Remember that the electrons only move through the wires in the external circuit and not through the electrolyte solution.
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