

Partial pressure and mole fraction expressions
Working out mole fractionsA sample of 0.25 mole of nitrogen and 0.75 mole of hydrogen were reacted together to form ammonia. The equilibrium amount of nitrogen was 0.16 mole.
N2 (g) + 3H2 (g) ⇌ 2NH3 (g)
Calculate the mole fractions of nitrogen, hydrogen and ammonia.
Answer
Write out the equation and record the initial, the change and the equilibrium amounts:

You can check you have the mole fractions correct by adding them up and making sure they come to 1:0.195 + 0.585 + 0.220 = 1
Finding KpHydrogen and bromine were mixed in a flask in a 1: 1 ratio and allowed to reach equilibrium at 450 K. When equilibrium had been achieved the total pressure in the flask was 140 kPa and the mole fraction of bromine was 0.35.The equation for the reaction is
H2 (g) + Br2 (g) ⇌ 2HBr (g)
Determine the partial pressures for each gas at equilibrium and the value of Kp

Finding Partial PressureKp for the dissociation equilibrium reaction of nitrogen monoxide is 0.0021.
2NO (g) ⇌ N2 (g) + O2 (g)
If pure NO is introduced into a reaction flask at an initial pressure of 100 kPa, what is the equilibrium partial pressure of nitrogen?


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