The driving force behind chemical reactions cannot be explained by enthalpy changes alone as it makes not sense for chemical to end up in a less stable higher energy state in endothermic reactions
CaCO3(s) → CaO(s) + CO2(g)
H2O(s) → H2O(l)
Melting a solid will cause the particles to become more disordered resulting in a higher entropy state
Make sure you don’t confuse the system with your surroundings!The system consists of the molecules that are reacting in a chemical reaction.The surroundings are everything else such as the solvent, the air around the reaction, test-tube, etc.
ΔSsystemꝋ = ΣΔSproductsꝋ - ΣΔSreactantsꝋ
(where Σ = sum of)
N2(g) + 3H2(g) ⇋ 2NH3(g)
ΔSsystemꝋ = (2 x ΔSꝋ(NH3)) - (ΔSꝋ(N2) + 3 x ΔSꝋ(H2))
Calculating entropy changesCalculate the entropy change of the system for the following reaction:
2Mg (s) + O2 (g) → 2MgO (s)
Sꝋ[Mg(s)] = 32.60 J K-1 mol-1
Sꝋ[O2(g)] = 205.0 J K-1 mol-1
Sꝋ[MgO(s)] = 38.20 J K-1 mol-1
Answer
ΔSsystemꝋ = ΣΔSproductsꝋ - ΣΔSreactantsꝋ
ΔSsystemꝋ = (2 x 38.20) - (2 x 32.60 + 205.0)
= -193.8 J K-1 mol-1
Use the stoichiometry of the equation and the correct state of the compounds when calculating the entropy change of a reaction.
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