The basic principle of a Born-Haber cycle
Drawing a Born-Haber cycle step 1
Na (s) → Na (g) ΔHatꝋ = +108 kJ mol -1
½Cl2 (g) → Cl (g) ΔHatꝋ = +121 kJ mol -1
Drawing a Born-Haber cycle step 2 - creating the gaseous atoms
Na (g) → Na+ (g) + e– ΔHieꝋ = +500 kJ mol-1
Cl (g) + e– → Cl- (g) ΔHeaꝋ = -364 kJ mol-1
Drawing a Born-Haber cycle step 3 - creating the gaseous ions
Na(s) + ½Cl2 (g) → NaCl (s) ΔHfꝋ = -411 kJ mol -1
Na+(g) + Cl-(g) → NaCl (s) ΔHlattꝋ
Drawing a Born-Haber cycle step 4 - completing the cycle
Constructing a Born-Haber cycle for KClConstruct a Born-Haber Cycle which can be used to calculate the lattice energy of potassium chloride.
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Constructing a Born-Haber cycle for MgOConstruct a Born-Haber Cycle which can be used to calculate the lattice energy of magnesium oxide.
Answer
When constructing Born-Haber cycles, the direction of the changes is important, but the relative size of the steps does not matter so don't worry if the steps don't correspond to the magnitude of the energy changes.You don't need to show the energy axis in a Born-Haber cycle, but you do need to show the electron(s) in the ionisation step otherwise you might lose marks in an exam.
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