Writing overall redox reactions
Manganate(VII) ions (MnO4- ) react with Fe2+ ions in the presence of acid (H+) to form Mn2+ ions, Fe3+ ions and water
Write the overall redox equation for this reaction
Answer
Step 1: Write the unbalanced equation and identify the atoms which change in oxidation state
Step 2: Deduce the oxidation state changes
Step 3: Balance the oxidation state changes
Step 4: Balance the charges
Step 5: Finally, balance the atoms
Cu + H2O → CuO + H2
(Cu has gained an oxygen and is oxidised)
2NH3 + 3Br2 → N2 + 6HBr
(NH3 has lost hydrogen and is oxidised)
Cu2+ + Mg → Mg2+ + Cu
(Mg has lost two electrons and is oxidised)
Cu2+ + Mg → Mg2+ + Cu
(change in ox. no. of Mg is +2 thus Mg is oxidised)
Cu+ H2O → 2CuO + H2
(H2O has been reduced)
2NH3+ 3Br2 → N2 + 6HBr
(Br has been reduced)
Cu2+ + Mg → Mg2+ + Cu
(Cu has been reduced)
Cu2+ + Mg → Mg2+ + Cu
(the change in oxidation state of Cu is -2 thus Cu is reduced)
Cu2++ Mg → Mg2+ + Cu
(Cu has been reduced and Mg has been oxidised)
Oxidation and reductionIn each of the following equations, state which reactant has been oxidised and which has been reduced.
Answer
Answer 1:
Answer 2:
Answer 3:
Example of a disproportion reaction in which the same species (chlorine in this case) has been both oxidised and reduced
Balancing disproportionation reactionsBalance the disproportionation reaction which takes place when chlorine is added to hot concentrated aqueous sodium hydroxideThe products are Cl- and ClO3- ions and water
Answer
Step 1: Write the unbalanced equation and identify the atoms that change in oxidation state:
Step 2: Deduce the oxidation state changes:
Step 3: Balance the oxidation state changes:
Step 4: Balance the charges
Step 5: Balance the atoms
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