Edexcel IGCSE Maths 复习笔记 4.10.1 Sine & Cosine Rules, Area of a Triangle - Basics
sin 90° =1 – so if one of the angles is 90°, this becomes ‘SOH’ from SOHCAHTOA
a2 = b2 + c2 – 2bc cos A
cos 90° = 0 so if A = 90°, this becomes Pythagoras’ Theorem
Area = ½ ab sin C
b2 = a2 + c2 - 2ac cos B
c2 = a2 + b2 - 2ab cos C
Note that it’s always the angle between the two sides in the final term
Note that it’s always the angle between the two sides on the right-hand side –you can always just relabel the sides and angles of your triangle, though, instead of worrying about alternate versions of the last two formulas
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