2016 AP Physics C物理C—Electricity and Magnetism电磁真题系列之Practice Exam简答题免费下载

历年AP Physics物理学系列

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2016 AP Physics C Electricity&Magnetism Practice Exam Free-Response Questions Free Download

2016 AP 物理C电磁模考简答题部分免费下载

此套题仅 p II含有简答题，

共计时45分钟，共3题

占总分50%

每道大题可能含有不同数量的小题

可以使用计算器

部分真题预览：

1）A rod of length L lies along the x-axis with its left end at the origin, as shown in the figure above. The rod has a nonuniform linear charge density λ = αx , where α is a positive constant.

1. Determine the units of the constant α .
2. Derive an expression for the total charge on the rod. Express your answer in terms of α , L, and physical constants, as appropriate.
   The rod is replaced with one of the same length but with a uniform positive linear charge density λ₀.
3. Show that the electric field at point A, which is a distance b to the left of the rod, has a magnitude of
4. A proton is placed at point A, at position (–b, 0), near the positively charged rod and released from rest.
   1. Sketch a graph of the horizontal component of the acceleration of the proton x a as a function of its position α_x for the region in which the proton travels after it is released. Sketch any asymptote, but do not indicate its value.
   2. Sketch a graph of the horizontal component of the velocity of the proton x v as a function of its position v_x for the region in which the proton travels after it is released. Sketch any asymptote but do not indicate its value.
   3. Instead of a proton, an alpha particle (a particle with twice the charge and four times the mass of a proton) is now placed at point A. Is the magnitude of the initial acceleration of the alpha particle greater than, less than, or equal to the magnitude of the initial acceleration of the proton from part (d)i?
      ____ Greater than ____ Less than ____ Equal to
5. Using the equation from part (c), show that the magnitude of the electric field at a point on the x-axis very far away from the rod is approximately equal to the electric field due to a point charge of magnitude Q = λ₀L located at the origin.